Question

a body starts from rest and travels with an acceleration of 2m/s² .after t seconds its velocity is 10m/s then t is​

Answer 1

Answer:

t = 5 sec

Explanation:

Given, A body starts from rest and travels with an acceleration of 2m/s² and attains a velocity of 10m/s after t sec.

Find ‘t’

We know,

$\sf \longrightarrow \: a = \dfrac{(v - u)}{t}$

Where,

• a(acceleration) = 2m/s²
• v(final velocity) = 10m/s
• u(initial velocity) = 0m/s [ Since it is at rest]

From the given parameters,

$\sf \implies \: 2 = \dfrac{(10 - 0)}{t}$

$\sf \implies \: 2 = \dfrac{10}{t}$

$\sf \implies \: t = \dfrac{10}{2}$

$\sf \implies \: t = 5s$

∴ The value of ‘t’ is 5sec

________________________

Formula used:

$\sf \longrightarrow \: Acceleration = \dfrac{(v - u)}{t}$

Where, v denotes the final velocity, u denotes the initial velocity and t is the time.

Answer 2

☀️  Given that :

        A body starts from rest

        Acceleration of body is 2m/s²

        After t seconds it's final velocity is 10m/s

Need to find : Value of t

⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━

To Calculate the value of t we have to substitute the values in the first equation of motion ::

⚝ v = u + at

Where,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time taken

T H E R E F O R E,

=> 10 = 0 + [ 2 × t ]

=> 10 = 0 + 2t

=> 2t = 10 - 0

=> 2t = 10

=> t = 10/2

=> t = 5s

[ Note : Initial velocity is taken zero because the body was initially at rest ]

⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━

• Henceforth, value of t is 5 seconds.