Question

A body starts from rest and travels with uniform acceleration of 3m/s2 and then decelerates to rest. if the total time of the journey is 10sec find maxmium velocity and total displacement. ​

Answer 1

Explanation:

u = 0

a1 = 3m/s^2

a2 = 2m/s^2

t = 10s

First apply

V = u + a1 t

v = 0 +3t

v = 3t eq1

Again it reaches to Velocity 0 after (10 -t) s

so

V = u + a2t

By eq1 v = 3t

0 = 3t - 2(10 - t)

-3t = -20 + 2t

t = 20s

Now bY eq 1.

V = 3t

= 3 × 20

= 60m/s

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