Question

A body starts from rest and travels with uniform acceleration of 3m/s and
then decelerates to rest. If the total time of journey is 10sec, find the:
a) Maximum velocity during the journey​

Answer 1

$\huge\boxed{\fcolorbox{cyan}{grey}{Solution}}$

u = 0

a1 = 3m/s^2

a2 = 2m/s^2

t = 10s

V = u + a1 t

v=3t -----equation 1

Again it reaches to Velocity 0 after (10 -t) s

V = u + a2t

V = u + a2t

t =20 s

V = 3t

3 X 20

60 m/s

Answer 2

Explanation:

u = 0

a1 = 3m/s^2

a2 = 2m/s^2

t = 10s

V = u + a1 t

v=3t -----equation 1

Again it reaches to Velocity 0 after (10 -t) s

V = u + a2t

V = u + a2t

t =20 s

V = 3t

3 X 20

60 m/s

ANSWER❤

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