Question

A body starts from rest and travels with uniform acceleration on a straight line. If its velocity after making a displacement of 32 meter is 8 m/s then it's acceleration is:- (A) 1 m/s^2 [One meter per second square] (B) 2 m/s^2 [Two meter per second square] (C) 3 m/s^2 [Three meter per second square] (D) 4 m/s^2 [Four meter per second square]

Answer 1

GiveN :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 8 m/s
• Distance travelled (s) = 32 m

To FinD :

• Acceleration of body

SolutioN :

Use 3rd equation of motion :

➜ v² - u² = 2as

➛ 8² - 0² = 2 * a * 32

➛ 64 - 0 = 64a

➛ 64 = 64a

➛ a = 64/64

➛ a = 1

$\therefore$ Acceleration of Body is 1 m/s².

Answer 2

$\large{\underline{\sf{\red{Find:\rightarrow}}}}$

Acceleration[a]??

$\small{\underline{\sf{\blue{Given:\rightarrow}}}}$

• Initial velocity [u]= 0m/s
• Final velocity [v]= 8m/s
• Displacement [s]= 32m

$\small{\underline{\sf{\green{Formula \ used:\rightarrow}}}}$

$\boxed{\bf{v^2-u^2= 2as }}$

$\small{\underline{\sf{\pink{SoLution:\rightarrow}}}}$

Put value in formula we get,

$\bf {\implies 8^2- 0^2= 2\times a \times 32}$

$\bf{\implies 64= a\times 64 }$

$\bf{{\implies a= 1}}$

$\boxed{\sf{\orange{Acceleration = (A) \ 1m/s^2\bigstar }}}$

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