Question

A body starts from rest and travels with uniform acceleration on a straight line . If its velocity after making a displacement of 32 m is 8 m/s , its acceleration is

Answer 1

Answer:

$acceleration=1m/s^{2}$

Explanation:

Given that, the acceleration of the body is constant.

So,   $v^{2}-u^{2}=2as$     ; where

                                         $v=final velocity \\u=initial velocity\\a=acceleration\\s=displacement$

Now,

               $v=8m/s\\ u=0m/s\\s = 32m\\a =?$

Substituting,

=>  $(8)^{2}-(0)^{2}=2(a)(32 )$

=>  64 - 0 = 64(a)

=>  a = 1 $m/s^{2}$.

Answer 2

Given:

Initial velocity = 0 m/s

Final velocity = 8 m/s

Displacement = 32 m

To find:

The acceleration of the body

Solution:

We know that,

$v^2=u^2+2aS$

where,

$v$ = final velocity = 8 m/s

$u$ = initial velocity = 0 m/s

$a$ = acceleration

$S$ = displacement = 32 m

Now, putting the values,

⇒$(8)^2=0^2+2$×$a$×$32$

⇒$64=64a$

⇒$a=1 m/s^2$

Hence, the acceleration of the body is $1 m/s^2$.