Question

A body starts from rest and travels with uniform acceleration on a straight line. If its velocity after making a displacement of 32 meter is 8 m/s then it's acceleration is:- (A) 1 m/s^2 [One meter per second square] (B) 2 m/s^2 [Two meter per second square] (C) 3 m/s^2 [Three meter per second square] (D) 4 m/s^2 [Four meter per second square]​

Answer 1

Answer :

Initial velocity = zero

Final velocity = 8m/s

Displacement = 32m

We have to find acceleration of body$.$

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Since acceleration of body has said to be constant throughout the period of motion, We can apply equation of kinematics to solve this question.

Let's apply 3rd eq. of kinematics :

⇒ v² - u² = 2as

⇒ 8² - 0² = 2a(32)

⇒ 64 = 64a

⇒ a = 1m/s²

Hence, acceleration of body is 1m/s².

Answer 2

Question :

• A body starts from rest and travels with uniform acceleration on a straight line. If its velocity after making a displacement of 32 meter is 8 m/s then it's acceleration is:-

Given :

• initial velocity = 0 m/s
• distance covered = 32 m
• final velocity = 8 m /s

To find :

• acceleration

Solution :

As the body moves with uniform acceleration we can use the third equation of motion in order to solve this question .

As per the formula ,

$\bigstar \large \boxed{\mathtt{ {v}^{2} = {u}^{2} + 2as}}$

here ,

• v = final velocity
• u = initial velocity
• a = acceleration
• s = distance

Substituting the given values in the above equation we get ,

$\rightarrow \mathtt{ {v}^{2} = 2as}$

$\rightarrow \mathtt{ a = \dfrac{ {v}^{2} }{2s} }$

$\rightarrow \mathtt{ a = \dfrac{ 64}{2 \times 32} }$

$\rightarrow \mathtt{ a = \dfrac{ 64}{64} }$

$\rightarrow \mathtt{ \red{ a = 1 \dfrac{m}{ {s}^{2} } }}$

The acceleration of the body is 1 m/s²