A body starts from rest and travels with uniform acceleration of 2 metre per second if its velocity is V after making a displacement of 9 M then the V is
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Appropriate Question :
A body starts from rest and travels with uniform acceleration of 2 m/s², if its velocity is v after making a displacement of 9m . Then find the value of 'v'.
Answer:
6 m/s
Explanation:
As per the provided information in the given question, we have :
- Initial velocity, u = 0 m/s [Starts from rest]
- Acceleration, a = 2 m/s²
- Displacement, s = 9 m
We have been asked to calculate the final velocity, v.
By using the third equation of motion,
• v² ― u² = 2as
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- s denotes distance/displacement
On substituting values,
→ v² ― (0)² = 2 × 2 × 9
→ v² ― 0 = 36
→ v² = 36
→ v = √36
→ v = 6
→ Final velocity = 6 m/s
Therefore, the v is 6 m/s.
Learn More :
Equations of motion :
- v = u + at
- s = ut + ½at²
- v² — u² = 2as
Where,
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- t denotes time
- s denotes distance/displacement
Answer:
As a result, the v is 6 m/s.
Explanation:
We have the following information based on the information supplied in the given question:
Initial velocity, u = 0 m/s [Starts from rest]
Acceleration, a = 2 m/s²
Displacement, s = 9 m
We've been given the task of calculating the final velocity, v.
By using the third equation of motion,
• v² ― u² = 2as
v denotes final velocity
u denotes initial velocity
a denotes acceleration
s denotes distance/displacement
On substituting values,
→ v² ― (0)² = 2 × 2 × 9
→ v² ― 0 = 36
→ v² = 36
→ v = √36
→ v = 6
→ Final velocity = 6 m/s
Therefore, the v is 6 m/s.
More information :
Equations of motion :
v = u + at
s = ut + ½at²
v² — u² = 2as
Where,
v denotes final velocity
u denotes initial velocity
a denotes acceleration
t denotes time
s denotes distance/displacement