Question

A body starts from rest and travels with uniform acceleration of 3m/s^2 and then decelerates at uniform rate of 2m/s^2 again to come down to rest if the total time of journey is 10 seconds then find the maximum velocity during the journey and total displacement

Answer 1

(3-2)m/s^2=1m/s^2
1*10=10

Answer 2

u = 0
a1 = 3m/s^2
a2 = 2m/s^2
t = 10s

First apply

V = u + a1 t

v = 0 +3t

v = 3t eq1

Again it reaches to Velocity 0 after (10 -t) s

so
V = u + a2t

By eq1 v = 3t

0 = 3t - 2(10 - t)

-3t = -20 + 2t

t = 20s

Now bY eq 1.

V = 3t

= 3 × 20

= 60m/s

Thanks