Question

A body starts from rest and with a uniform acceleration of 10 m.s-2 for 5 seconds. During the next 10 seconds It
moves with uniform velocity. The total distance travelled by the body is​

Answer 1

Answer:

625

Explanation:

$The \: initial \: velocity \: travelled \: is \: = 625$

$The \: accleration \: is \: \alpha = 10m/ {sec}^{2}$

$The \: time \: is \: \: t = 5s$

$Apply \: the \: equation \: of \: motion \:</p><p></p><p> \\ v=u+at$

$The \: velocity \: is \: \\v = 0 + 10.5 = 50m/sec$

now let's see the case for next 10 sec

here speed is constant=50m/s

now using x=vt

x=50×10

x=500m

total distance =125+500=625m

hope it helps you ♥️♥️