A body starts from rest and with a uniform
acceleration of 10 m/s² for 5 seconds. During the
next 10 seconds it moves with uniform velocity.
The total distance travelled by the body is-
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EXPLANATION.
- GIVEN
A body starts from rest and with a uniform
acceleration of 10 m/s^2
Time = 5 seconds.
next 10 seconds it moves with uniform velocity.
To find the total distance travelled by
the body.
according to the question,
body starts from rest = u = 0
For first 5 seconds
acceleration = 10 m/s^2
From Newton second equation of
kinematics.
S = Ut + 1/2 at^2
=> s = 0 + 1/2 X 10 X 5 X 5
=> s = 125 m
From Newton first equation of
kinematics.
v = u + at
=> v = 0 + 10 X 5
=> v = 50 m/s
For the next 10 seconds.
v = 50 m/s
t = 10 seconds
s = vt
=> s = 50 X 10
=> s = 500 m
Therefore,
Total distance travelled by the body
=> 500 + 125 = 625 m
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