Question

a body starts from rest and with a uniform acceleration of 10 M per second square for 5 seconds during the next 10 seconds it moves with a uniform velocity the total distance travelled by the body is

Answer 1

u =0 m/s
a =10 m/s^2
t =5s
v=?
by Newton's first law of motion,
v= u + at =0 +10×5 =50m/s
By Newton's second law,
S= ut + at^2/2 =0 + 10×5×5/2 = 125m

Now,
constant velocity =50m/s
time taken =10s
distance = 50× 10 = 500m

Therefore total distance travelled = 125 + 500
=625 m

Answer 2

Hello...
The body starts from rest
Thus.. u=0 ,a=10m/s^2 ,t=5sec
Now...
S1=ut +1/2at^2
S1=0+125
S1=125metres
Now.... v=u +at
=0+10×5
=50m/s
Now it moves with a uniform velocity of 50m/s...... so ..... speed=dist./time
10 × 50 = d
So... s2=500m
Now....
total displacement = s1+s2 =125+500 = 625m