Question

a body starts from rest and with a uniform acceleration of 10 m/s for 5sec during the next 10 sec it moves with uniform velocity the total distance travelled bt the body is:-

Answer 1

body starts from rest that is u=0
now for first 5sec. a=10m/s^2
using 2nd eqn of motion.
x=ut+1/2at^2.
x=0+ 1/2×10×5×5
therefore x = 125m
now using first eqn of motion to find final speed
v=u+at
v=0+10×5
v=50 m/s

now let's see the case for next 10 sec
here speed is constant=50m/s
now using x=vt
x=50×10
x=500m
total distance =125+500=625m



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Answer 2

Explanation:

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