Math, asked by Sonx, 9 months ago

A body starts from rest at point A and travels upto point B with constant acceleration of 10m/s^2 in 4 secs. then from point B it travels to point C with constant acceleration of 20m/s^2 in 8 secs

FIND 1. velocity of the body at point B

2. velocity of the body at point C

3. total distance travelled by the body?

Answers

Answered by Aaliyakumar123679
1

Answer:

Distance covered is equal to the area under velocity-time graph.

Distance in last two seconds s  

2 =  2 1 ×8×2=8 m

Total distance =  

2 1 ×8×(6+2)=32 m

Fraction of the distance covered by the body in the last two seconds of its motion to total distance traveled by it in all the seven seconds is  8/32=1:4  

December 20, 2019

Step-by-step explanation:

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