A body starts from rest at point A and travels upto point B with constant acceleration of 10m/s^2 in 4 secs. then from point B it travels to point C with constant acceleration of 20m/s^2 in 8 secs
FIND 1. velocity of the body at point B
2. velocity of the body at point C
3. total distance travelled by the body?
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Answer:
Distance covered is equal to the area under velocity-time graph.
Distance in last two seconds s
2 = 2 1 ×8×2=8 m
Total distance =
2 1 ×8×(6+2)=32 m
Fraction of the distance covered by the body in the last two seconds of its motion to total distance traveled by it in all the seven seconds is 8/32=1:4
December 20, 2019
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