Question

a body starts from rest attains a velocity of 20 metre per second undergoes a displacement of 50 M what is the acceleration​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=4\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial\: velocity(u) =0 \: m/s \\ \\ \tt : \implies Final\:velocity(v) = 20 \: m/s\\ \\ \tt: \implies Displacement(s) = 50\:m \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Acceleration(a) = ?$

• According to given question :

$\tt \circ \: Initial \: velocity =0\: m/s \\ \\ \tt \circ \:Final\:velocity = 20 \: m/s \\ \\ \tt \circ \:Displacement = 20 \: m$

$\tt : \implies {v}^{2} = {u}^{2} + 2as \\ \\ \tt : \implies {20}^{2} = {0}^{2} + 2 \times a \times 50 \\ \\ \tt : \implies 400 = 100 \times a \\ \\ \tt : \implies a = \frac{400}{100} \\ \\ \green{\tt : \implies a = 4 \: m /{s}^{2} }$

$\blue{\bold {Some \: related \: formula}} \\ \orange{\tt \circ \: v = u+at} \\ \\ \orange{\tt \circ \: s = ut+\frac{1}{2}at^{2}}$

Answer 2

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 20 m/s
• Displacement (s) = 50 m

We know that , the third equation of motion is given by

$\large \mathtt{ \fbox{ {(v)}^{2} - {(u)}^{2} = 2as}}$

Thus ,

(20)² - (0)² = 2 × a × 50

400 = 100 × a

a = 400/100

a = 4 m/s²

Hence , the acceleration is 0.2 m/s²

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