a body starts from rest attains a velocity of 4m/s in 4s.fimd the displacement travelled
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A car starting from rest attains a velocity of 20ms-1 in 5 sec, what is the distance covered by the car?
For this, we have to use the equations of motion. first, we have to find the acceleration. Then use the third equation of motion to find displacement.
a=v-u/t
a=20–0/5
a=20/5
a=4 ms^2 (now we know the acceleration)
We have to use the third equation of motion to find displacement.
s=u*t +1/2*a*t^2
s=0*5+1/2*4*5^2
s=1/2*4*5^2
s=2*5^2
s=50 meters
SO, the answer is 50 meters .
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