Question

A body starts from rest has accelration of 20m\s².calculate its velocity after travelling a distance of 10m

Answer 1

Given :

• Acceleration,a = 20 m/s²
• Initial velocity,u = 0 m/s
• Distance,s = 10 m

To Find :

Velocity of a body after travelling a distance of 10m

${\purple{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion .

$\bf\:v=u+at$

$\bf\:s=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2as$

and $\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

${\underline{\sf{Answer}}}$

From the third equation of motion,we have

$\sf\:v{}^{2}=u{}^{2}+2as$

Put the given values then ,

$\sf\implies\:v{}^{2}={0}^{2}+2\times20\times10$

$\sf\implies\:v{}^{2}=0+40\times10$

$\sf\implies\:v{}^{2}=400$

$\sf\implies\:v=\sqrt{400}$

$\sf\implies\:v=20ms{}^{-1}$

Hence,the velocity of a body is 20 m/s.

Answer 2

✯✯ QUESTION ✯✯

A body starts from rest has acceleration of 20m\s².Calculate its velocity after travelling a distance of 10m ..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Initial\:Velocity(u)=0m/s}$

$\longmapsto\tt{Acceleration(a)=20{m/s}^{2}}$

$\longmapsto\tt{Distance\:travelled(s)=10m}$

$\longmapsto\tt{Final\:Velocity(v)=?}$

➥Using 3rd Equation : -

$\longmapsto\tt{\small{\boxed{\bold{\bold{\green{\sf{{v}^{2}-{u}^{2}=2as}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{{v}^{2}-{(0)}^{2}=2\times{20}\times{10}}$

$\longmapsto\tt{{v}^{2}=40\times{10}}$

$\longmapsto\tt{{v}^{2}=\sqrt{400}}$

$\purple\longmapsto\:\large\underline{\boxed{\bf\blue{v}\pink{=}\red{20}}}$

☛ So , The final velocity is 20m/s...