A body starts from rest is uniformly accelerated for 15 s. The distance travelled in first 5 s is x₁, next 5 s is x₂ and the last 5 s is x3. Then
Answers
Answer:
1 : 3 : 5
In this question we use the formula:
S = 1/2 a x t^2
Distance traveled by the body in first 10 sec (x1):
S = 1/2 a x t^2
Substituting the values known to us from the question in this equation we get:
=> x1 = 1/2 x a x 10^2
=> x1 = 100 x a x 1/2
=> x1 = 50 a
Distance traveled by the body in the next 10 sec (x2):
S = 1/2 a x t^2 - 1/2 x a x 10^2
Substituting the values known to us from the question in this equation we get:
=> x2 = 1/2 x a x 20^2 - 1/2 x a x 10^2
=> x2 = 200 a - 50 a
=> x2 = 150 a
Calculating the distances traveled in the last 10 sec (x3):
S = 1/2 a x t^2 - 1/2 x a x 10^2 - 1/2 x 20^2
Substituting the values known to us from the question in this equation we get:
=> x3 = 1/2 a x 30^2 - 1/2 x a x 10^2 - 1/2 x 20^2
Solving we get:
=> x3 = 1/2 x a x 500
=> x3 = 250 a
Now calculating x1:x2:x3
= 50 a : 150 a : 250 a
In simplest ratio we get:
= 1 : 3 : 5
Therefore, the ratio of x1:x2:x3 is 1 : 3 : 5.
Answer:
The ratios of x1 : x2 : x3 = 1 : 3 : 5
Explanation:
Given :
Initial Velocity (u) = 0 m/s
Thr body is accelerated for 15 seconds.
This acceleration is divided into three parts, 5 seconds each.
Let time (t) = 5 seconds.
To be Calculated -
x1 : x2 : x3
Formula to be Used :
where s is the distance covered by the body, u is initial velocity, t is time taken and a is acceleration.
Calculations :
For the first 5 seconds,
u = 0 m/s
For the next 5 seconds,
For the last 5 seconds,
Now, The ratios of x1 : x2 : x3 = 1 : 3 : 5 .
Concept :
There are three equations of motion :
These equations are used when acceleration is constant for solving any problem.
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