A body starts from rest moves with uniform acceleration of 10m/s2 for 10second then it deaccelerates by 5m/2 and comes to rest .the distance covered by the body is
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v=u+at
v=10×10=100m/s
v=u+at
0=100+5×t
t=20s
total distance=1600
v=10×10=100m/s
v=u+at
0=100+5×t
t=20s
total distance=1600
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