Math, asked by chandrakumar2066, 1 month ago

a body starts from rest moving with uniform acceleration find the ratio of distances covered by it in 3rd second and 7th second​

Answers

Answered by baghelsharmila409
1

Answer:

Correct option is

A

n

2

n

2

1

Distance travelled by a body in 'n'th second is

s

n

=u+

2

a

(2n−1)

Distance travelled in 'n' seconds is

s=un+

2

1

an

2

u is zero since the body starts from rest.

s

s

n

=

2

1

an

2

2

a

(2n−1)

Therefore, the ratio =

s

s

n

=

n

2

n

2

1

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