Question

A body starts from rest, reaches a velocity of 8m/s in 4 second. Find the acceleration.
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Answer 1

Answer:

2metrepersecond

Explanation:

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Answer 2

Answer:

Given :-

• A body starts from rest, reaches a velocity of 8 m/s in 4 seconds.

To Find :-

• What is the acceleration.

Formula Used :-

$\clubsuit$ First Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v =\: u + at}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Solution :-

Given :

• Final Velocity (v) = 8 m/s
• Initial Velocity (u) = 0 m/s
• Time Taken (t) = 4 seconds

According to the question by using the formula we get,

$\longrightarrow \sf\bold{\underline{\purple{v =\: u + at}}}$

$\longrightarrow \sf 8 =\: 0 + a(4)$

$\longrightarrow \sf 8 =\: 0 + 4a$

$\longrightarrow \sf 8 - 0 =\: 4a$

$\longrightarrow \sf 8 =\: 4a$

$\longrightarrow \sf \dfrac{\cancel{8}}{\cancel{4}} =\: a$

$\longrightarrow \sf \dfrac{2}{1} =\: a$

$\longrightarrow \sf 2 =\: a$

$\longrightarrow \sf\bold{\red{a =\: 2\: m/s^2}}$

${\small{\bold{\underline{\therefore\: The\: acceleration\: of\: the\: body\: is\: 2\: m/s^2\: .}}}}$

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★ EXTRA INFORMATION ★

➲ First Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\purple{v =\: u + at}}}$

➲ Second Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\purple{s =\: ut + \dfrac{1}{2}at^2}}}$

➲ Third Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\purple{v^2 =\: u^2 + 2as}}}$

where,

• s = Distance Covered
• u = Initial Velocity
• v = Final Velocity
• a = Acceleration
• t = Time Taken