Question

A body starts from rest the ratio of distances travelled in first two
seconds to next two seconds is
(A)1/3
(B)1/2
(C)3/4
(D)2/3

Answer 1

Answer:

Option (a) is correct

Explanation:

Let suppose acceleration be a

And we know from equation of motion

s=ut +0.5at^2

So,in first 2 sec, u=0(intial velocity)

So, s= 0+0.5a(4)=2a

Now for next 2 sec the final velocity of first 2 sec become intial velocity of next 2 sec

So,

V=u+at=0+2a=2a

Now for next to sec, u =2a

s=2a(2)+0.5a(4)

s=6a

REQUIRED RATIO=2a/6a=1/3

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