Question

a body starts from rest travel within uniform acceleration of 5 metre per second square find speed after 5 second and distance travelled in 5 second​

Answer 1

Given:-

• Initial velocity=u=0m/s
• Acceleration=a=5m/s^2
• Time=t=5s

To find:-

• Final velocity=v
• Distance=s

Answer:-

According to first equation of motion.

$\boxed{\sf v=u+at}$

$\\ \sf\longmapsto v=0+5(5)$

$\\ \bf\longmapsto v=25m/s$

According to 2nd equation of motion

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto s=0(5)+\dfrac{1}{2}\times 5\times 5^2$

$\\ \sf\longmapsto s=5+\dfrac{125}{2}$

$\\ \sf\longmapsto s=5+62.5$

$\\ \sf\longmapsto s=67.5m$