Question

a body starts from rest under uniform acceleration. if the distance covered by it in the 3rd second is 3m, then the distance cover in 5th second is?

Answer 1

u=0

s=3

t=3

s=ut+1/2at^(2)

=>3=0+a3^(2)

=>a= 3/9

=>a=1/3m/s^(2)

Now t= 5

u= 0

a=1/3

s=ut +1/2at^(2)

=0+1/2 × 1/3 × 5 × 5

=25/6 metres or 4.1666... metres.