Question

A body starts from rest what is the ratio of distance travelled by body during 4th and 3rd second

Answer 1

Explanation:

Consider the second equation of motion :-

s=ut+1/2a(t)^2

As body starts from rest so u=0 and we have

s=1/2a(t)^2

Here, ‘a’ the acceleration is considered constant.

Now for t=3 & t=4 , the ratio would be 9/16

Just square of 3/4.