A body starts from rest what is the ratio of distance travelled by body during 4th and 3rd second
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Explanation:
Consider the second equation of motion :-
s=ut+1/2a(t)^2
As body starts from rest so u=0 and we have
s=1/2a(t)^2
Here, ‘a’ the acceleration is considered constant.
Now for t=3 & t=4 , the ratio would be 9/16
Just square of 3/4.
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