Question

A body starts from rest. What is the ratio of the distance traversed by it during the 4th and the 3rd second?

Answer 1

Answer:

7:5

Explanation:

the ratio of the distance traveled by it is

1:3:5:7...........

Answer 2

Answer:

distance travelled in nth second = Sn= u+g/2(2n-1)

Explanation:

Sn= u+g/2(2n-1)

initial velocity =u = 0

Sn= g/2(2n-1)

ratio

S4th/S3rd = (2×4 - 1) / (2×3 - 1)

ratio= 7/5 = 7:5