Physics, asked by pawarswaranti, 1 year ago

A body starts from rest. What is the ratio of the distance travelled by the body during fourth and third
second ?​

Answers

Answered by aryan12326
1

Answer:

The formula is

Sn= u+a/2(2n-1)

For t=n=3

S3= 0+10/2(5)

S3= 50/2 m

Similarly,

S4= 0+10/2(7)

S4= 70/2m

S3/S4= 50/2×2/50

S3:S4= 5:7

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