a body starts from rest.what is the ratio of the distance travelled by the body in 4th and 3rd second
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distance travelled Sn in nth second is given by
Sn=u+a/2(2n-2)
a is acceleration,u is initial velocity
so
S4=a/2(6)=3a
S3=a/2(4)=2a
the ratio is 3/2
Sn=u+a/2(2n-2)
a is acceleration,u is initial velocity
so
S4=a/2(6)=3a
S3=a/2(4)=2a
the ratio is 3/2
jishnu075:
The ratio is 7/5
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