Question

A body starts from rest what is the ratio of the distance travelled by the body during the 4th and 3th second​

Answer 1

Given :

Initial velocity of the body = zero

To Find :

Distance travelled by the body during the 4th and 3rd second of the journey$.$

Solution :

Distance covered by body during the nth second of journey is given by

• Sₙ = u + a/2 (2n - 1)

» Sₙ denotes distance

» u denotes initial velocity

» a denotes acceleration

» n denotes number of second

A] Distance travelled in 4th second :

➙ S₄ = u + a/2 (2n - 1)

➙ S₄ = 0 + a/2 [2(4) - 1]

➙ S₄ = a/2 (8 - 1)

➙ S₄ = 7a/2

B] Distance travelled in 3rd second :

➙ S₃ = u + a/2 (2n - 1)

➙ S₃ = 0 + a/2 [2(3) - 1]

➙ S₃ = a/2 (6 - 1)

➙ S₃ = 5a/2

By taking the ratio :

➛ S₄ / S₃ = (7a/2) / (5a/2)

➛ S₄ : S₃ = 7 : 5