Question

A body starts from rest, what is the ratio of the distance travelled by the during the 4th and 3rdsecond ?

Answer 1

8a:4.5a

The acceleration should be given

Answer 2

Explanation:

we use second equation of motion s=ut+ 1/2 at ^2

As body starts from rest u=0 and we have s=1/2 at ^2

Here 'a' the acceleration is considered constant

Now for t=3 and t= 4

just square 3/4

the ratio would be 9/16

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