Question

A body starts from rest . what is the ratio of the distance travelled by the body during the 4th and 3rd second

options are (a) 7/5 (b) 5/7 (c) 7/3 (d) 3/7

pls answer with solution or it will be marked as offensive .

Answer 1

Distance travelled by a uniformly accelerating body = ut+12at2

If the body starts from rest, u=0

Hence s=12at2

Distance travelled in 5s =

S5=12×a×52=252a… eqn (1)

Distance travelled in 4s =

S4=12×a×42=162a

Hence, distance travelled in the 5th second =

S5−S4=25–162a=92a… eqn (2)

Therefore, required ratio = eqn(1)eqn(2)=925