Question

A body starts from rest with a uniform acceleration of 2 meter per second square. Find the distance covered by the body in 2 seconds .​

Answer 1

distance covered in 1sec square= 2m

1sec square = 1x1

distance covered in 1sec= 2m

distance covered in 2sec=2sx2m

                                         =4m

Answer 2

$s = ut + \frac{1}{2} at {}^{2}$

where a is the distance, u is the initial velocity, a is acceleration and t is time.

so we have

u = 0 (since the body was at rest)

t = 2 sec

a = 2m/s^2

So we have  Distance :-

$(0 \times 2) + \frac{1}{2} \times 2 \times {2}^{2} \\\\\\ = 0 + {2}^{2} \\\\\\ = {2}^{2} \\\\ = 4$