Question

a body starts from rest with a uniform acceleration of 2 m s -2.find the distance covered by the body in 2s.

Answer 1

Hi there !!
Here's your answer

Initial velocity (u) = 0m/s [ the body starts from rest ]
Acceleration (a) = 2m/s²
Time (t) = 2 sec

To find the distance using the 2nd equation of motion,

s = ut + 1/2at²
s = 0 + 1/2 × 2 × 2²
s = 4

Thus,
The distance is 4m

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Hope you're helped :D

Answer 2

Hi,

Here is your answer,

Acceleration:- 2 m/s²

Time:- 2 second

Initial Velocity :- 0 m/s

We know that,

s = ut+1/2at²                 { Second equation of Motion }

s = 0 + 1/2 × 2 × (2)²

s = 4 m


Hope it helps you !