Question

A body starts from rest with a uniform acceleration of 5 m/s2 find the distance covered by the body in 2s.​

Answer 1

""" ❤️ Answer ❤️ """

S=

ut+

u= 0,a= 2m/s

2

,t= 2s

2

1

at

2

S=

0×

2+

2

1

×

2×

2 2

S=

4m

Answer 2

Given,

$\pink{ \boxed{ \boxed{ \begin{array}{cc} \sf \to \: initial \: velocity \: \: u = 0 \: \: \{ \bf \: rest \} \\ \\ \sf \to \: acceleration \: \: a = 5 \: m {s}^{ - 2} \\ \\ \sf \to \: \: time \: \: t = 2 \: s \end{array}}}}$

→ We have to find :

• Distance covered by the body = s

Solution :

$\orange{ \boxed{ \boxed{ \begin{array}{cc} \bf \: we \: know \: that \: : \\ \\ \rm \: s = ut + \frac{1}{2}a {t}^{2} \\ \\ = 0 \times 2 + \frac{1}{2} \times 5 \times {2}^{2} \\ \\ = 0 + \frac{1}{2} \times 5 \times {4}^{} \\ \\ = 5 \times 2 \\ \\ = 10 \: m\end{array}}}}$

So, distance covered by the body is 10 m