Question

A body starts from rest with a uniform acceleration of 6 m/s^2. Find the
distance covered by the body in (i)2seconds(ii)20 seconds *​

Answer 1

Answer :

Initial velocity of body = zero

Acceleration of body = 6m/s²

We have to find distance covered by body in

• 2 seconds
• 20 seconds

⧪ ATQ, acceleration of body is said to be constant throughout the motion, we can easily apply equation of kinematics to solve this question$.$

2nd eq. of kinematics is given by

• S = ut + 1/2(at²)

S denotes distance

u denotes initial velocity

a denotes acceleration

t denotes time

★ Distance covered in 2 seconds :

⭆ S = ut + 1/2(at²)

⭆ S = (0×2) + 1/2(6×2²)

⭆ S = 0 + 1/2(24)

⭆ S = 12m

★ Distance covered in 20 seconds :

⭆ S' = ut' + 1/2(at'²)

⭆ S' = (0×20) + 1/2(6×20²)

⭆ S' = 0 + 1/2(2400)

⭆ S' = 1200m

Cheers!