Question

a body starts from rest with an accelaration 4m/s^2. find the distance covered in 4second
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Answer 1

$\large{\underline{\sf{\red{Find:\rightarrow}}}}$

• Distance covered?

$\large{\underline{\sf{\orange{Given:\rightarrow}}}}$

• initial velocity [u]= 0m/s

• time = 4 sec

• acceleration= 4m/s²

$\large{\underline{\sf{\green{SoLution:\rightarrow}}}}$

By using kinematic eq' of motion,

$\boxed{\bf{ s= ut+\dfrac{1}{2} at^2}}$

$\bf{\implies s= 0\times 4+ \dfrac{1}{2}\times 4\times 4 }$

$\bf{\implies s= 8m}$

$\boxed{\sf{\blue{\therefore Distance=8m}}}$

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