a body starts from rest with an acceleration 2m/s2 till it attains the maximum velocity then retards to rest with 3m/s2. if total time taken is 10 second then maximum speed attained is
a) 12m/s b) 8m/s
c) 6m/s d) 4m/s
Answers
Answered by
9
a) 12 m/s.
the maximum speed attained will be 12m/s .
drawing the velocity-time graph will be helpful
a triangle will be formed
drop a perpendicular from the upper vertex to x-axis
now two triangles will be formed
since we know that the slope of v-t graph gives acceleration
apply tanΘ and get the answer
the maximum speed attained will be 12m/s .
drawing the velocity-time graph will be helpful
a triangle will be formed
drop a perpendicular from the upper vertex to x-axis
now two triangles will be formed
since we know that the slope of v-t graph gives acceleration
apply tanΘ and get the answer
Answered by
0
Given:
Acceleration a=2 m/sec²
Velocity v= 3 m/sec
Time taken in second t'=10 sec
To find:
Maximum speed attained to be
Solution:
First find the maximum velocity
V= u+at'
Putting above values
V= 2t' as u=0
Now find the V(f)
V(f)= V - 3(10-t')
As the body came to rest V(f)=0
0=V- 3(10-t')
V=3(10-t')
Putting above value
2t'=30-3t'
5t'=30
t'=6 sec
Time taken is 6 sec. So, option C is correct.
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