Physics, asked by haasini0318, 9 months ago

A body starts from rest with an acceleration of 0.5m/s^2. What will be its velocity when it has travelled a distance of 800 metre. How many seconds did it take to cover the distance.

Answers

Answered by rohitjha2005
1

Answer:

a=4 m/s2

s=800m

u=0 m/s

s=ut+ 1/2 at2

800=0+1/2*4*t2

800=2t2

400=t2

t=20 s

a=(v-u)/t

4=v-0/20

80=v

v=80 m/s

Explanation:

Answered by RamisKing
1

Explanation:

u = initial velocity = 0m/s

a = accleration = 0.5 m/s^2

s= distance = 800 meter

Formula

s = ut + (at^2)÷2

800 = 0 + (0.5×t^2)÷2

1600÷0.5 =t^2

3200 = t^2

t = time = square root of 3200

therefore

t = 56.56 sec

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