Question

A body starts from rest with an acceleration of 2 metre per second square. Calculate:(1) velocity after 5 seconds (2) the distance covered in 5 seconds (3) the distance covered by the body while achieving velocity of 40 metre per second

Answer 1

u=0, a=2 m/s^2

(1)v=u+at

v=at, where u=0

v=2×5=10 m/s

(2)s=ut+(1/2)at^2

=(1/2)at^2=(1/2)×2×25=25 m

(3)v^2=u^2+2as

v^2=2as

s= v^2/2a=1600/4=400 m

Answer 2

Answer:

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