Question

A body starts from rest with an acceleration of 4cm/sec^2.What will be its velocity after travelling a distance of 50c.m. How much distance shall be in 10 seconds after 50c.m point.​

Answer 1

Answer: 20 cm/s (0.2 m/s) and 700 cm (7 m)

Step-by-step explanation:

Initial velocity Vo = 0 cm/s  (∵ starts from rest)

acceleration a = 4 cm//s^2

distance, d = 50 cm

final velocity V =?

$V^2 - V_0^2 =2ad$

$V^2 -0 = 2*4*50\\V^2 = 400\\V =20$so, V =20 cm/s = 0.2 m/s

now starting from 50 cm with 20cm/s body travels for next 10 seconds, so

$d =Vt + \frac{1}{2}at^2$

$d = 50*10 + \frac{1}{2}*4*10^2\\ d = 500 + 2*100\\d = 700 cm$d = 700 cm = 7 m