Question

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A body starts from rest with uniform acceleration 2 ms. Find the distance covered by it in 5 s.​

Answer 1

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Answer 2

Answer:

Explanation:

S=1/2*(u+v)*t

S=ut+1/2*a*t*t

Here,

S is distance travelled

u is intial velocity

v is final velcoity

t is time taken

So,

S=0ms*5s+1/2*2ms*5s*5s

S=0m+1/2*2ms*25s

S=1/2*50m

S=25m

Answer is 25m