Physics, asked by mahendar5778, 11 months ago

a body starts from rest with uniform acceleration a, its velocity after n seconds is v. The dispalacement of the body in last 3 s is​

Answers

Answered by ranjithmalviya7
1

Answer:

Explanation:

The first formula used is S=ut+1/2at^2

Since started from rest initial velocity is zero

The underlined formula is used because acceleration is constant and we use basic formula acceleration = velocity/ time

The remaining part is solved in pic below

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Answered by shivam414189
1

Answer:

displacement s= 3v/2

Explanation:

let the equation of velocity

v= u + at

intial velocity u=0 ( start from rest)

v= a x n ........( for n seconds)

a = v/n

using equation

v2 -u2 = 2as........ ( s is displacement)

v2 = 2 x (v/n ) x s

solving

s = v x n / 2 ....... ( for n=3 second)

s = 3v/2

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