Question

A body starts from rest with uniform acceleration of 2 metre per second square . find the distance covered by the body in 2 seconds.

Answer 1

$s = ut + \frac{1}{2} at {}^{2}$
where a is the distance, u is the initial velocity, a is acceleration and t is time.
so we have
u = 0 (since the body was at rest)
t = 2 sec
a = 2m/s^2

So we have
distance=
$0 \times 2 + \frac{1}{2} \times 2 \times {2}^{2} \\ = 0 + {2}^{2} \\ = {2}^{2} = 4$
4 metre is the distance covered

Answer 2

by using the formula..
s=ut+1/2*at²