Question

a body starts from restvand acquire a velocity of 12m/s in5s calculate the accelerated and distance moved by the body​

Answer 1

Answer:

Acceleration-

v = U + AT (1st eq. of motion)

12= 0 + 5a

12/5= a

Thus, the accleration is 2.4 m/s2

The Distance travelled-

3rd Eq. of motion v2= u2+2as

12^2 = 0^2 + 2*2.4s

=> 144 = 4.8 s

=> 30 = s

Thus, 30 meters travelled

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