Question

A body starts from the origin and moves along the x-axis such that velocity at any instant is given by (4t3−2t) , where t is in second and velocity is in m/s. What is the acceleration of the particle, when it is at x=+2m

Answer 1

We know that a=dv/dt ..so

a=d(4t3-2t)/ft

a=12t2-2

Now given that x=+2 ..now put it in a

Thus a=12*4-2=46 m/s2