Question

A body starts from the rest position and acquired the velocity 56m/sec with acceleration 8m/sec sq find the distance traveled​

Answer 1

Explanation:

Given :

u=0

v = 56m /s

a = 8 m/ s sq

v^2 = u^2 +2a s

56 ×56 = 0 × 0 + 2 ×8 ×s

Therefore

Distance traveled , s = 56× 56 ÷ 2×8

= 28 × 7 = 196 m. Ans.