Physics, asked by pranesh562, 4 hours ago

A body starts motion with speed 4 m/s and moves along a straight horizon
path with uniform acceleration 2 m/s², after 5 sec the velocity of body will
14​

Answers

Answered by adarsharyan46
1

Answer:

14 m/s

Explanation:

Given :

u = 4 m/s

a = 2 m/s^{2}

t = 5 s

Find : v (Final velocity)

v = u + at (1st Equation of motion)

⇒ v = 4 + 2 × 5

⇒ v= 4 + 10

v= 14 m/s

Yes, your answer is correct !

Hope it helps :)

(If you find any mistakes, which I am sure there aren't any, then please contact me within 10 minutes of writing this answer, if not possible then please forgive me)

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Answered by ThunderGod1
0

Answer:

16 m/s

Explanation:

u ( Starting speed ) = 4 m/s

a ( acceleration ) = 2 m/s

t ( time ) = 5 sec

v ( velocity ) = 14 m/s

Because :

v = u + a × t

14 = 4 + 2 × 5

14 = 6 × 5

14 = 30

30 - 14

16 m/s

Hope it help

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