Question

a body starts moving from rest and in 10 seconds later it acquires a speed ofd 20m/s.
It maintains a constant speed for 5 seconds.Finally the body undergoes uniform retardation to rest in 10 seconds
a]DETERMINE THE TOTAL DISTANCE COVERED
b]calculate the average speed of the body
c]a stone is released from a height h, if the acceleration due to gravity is g, show that the velocity is v==2gh just before hitting the ground

Answer 1

Answer: a) total distance covered is 250m

b) average speed is 7.1m/s

c) for a freely falling body dropped from a height (h), initial velocity is 0.

Therefore, from v^2 = u^2 + 2as

u = 0, a = g, s = h

V^2 = 2gh

v = √2gh