A body starts moving from rest and travels with uniform acceleration for 4 seconds and gains velocity 30 m/s. Then it continues to move with uniform velocity for 4 seconds. Then it starts retarding uniformly and comes to rest in further 2 seconds. The total covered distance by the body within the interval 4 s to 10 s is
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From the question a graph is drawn above,
Area of v−t graph⟹ distance travelled
vavg=t1+t2+t38s
21vm×t1=s
t1=vm2s
t2×vm=2s
t2=vm2s
21×t3×vm=5s
t3=vm10s
vavg=vm2s+vm2s+vm10s8s
vmvavg=74
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Answer:
it is the answer of 4 sec to 10 is 120 ms/s
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