A body starts moving with acc 2 m/s find distan e travelled in 5th half second
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We are given acceleation and time and it says particle starts moving implies it starts from rest. So initial velocity is zero. And here we use this standard formula: s=ut+(1/2)a(t^2)
Using this formula we get our answer: 30.25m
or
we have to find distance in 5th half second.
Formula: s=ut+(1/2)a(t^2)
t^2 = (5/2)^2 – (2)^2 = 2.25 and using this in our formula distance travelled is: 2.25m
Using this formula we get our answer: 30.25m
or
we have to find distance in 5th half second.
Formula: s=ut+(1/2)a(t^2)
t^2 = (5/2)^2 – (2)^2 = 2.25 and using this in our formula distance travelled is: 2.25m
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