Question

A body starts siding on a rough horizontalsurface with a speed of 10m/s If the coefficient of friction is 0.2 Find the distance travelled by the body before coming to rest (g=10m/s^2) Options:
A: 15m
B: 25m
C: 35m
D: 40m
E: 55m​

Answer 1

Answer:

v=10 and u=0.2 and g=10

Soln.= Using F=uN then = umg (here N= mg)

So from above( ma=umg); we got a=ug

Now a=0.2×10 =2 m/s-2

Now using 2nd equation of motion

V2=u2+2as

0 = 10×10 +2×2×s

On solving it we got

S=100/4 = 25m

Hence we got answer

Explanation:

make me B........